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Hands-On Penetration Testing on Windows

Hands-On Penetration Testing on Windows

By : Phil Bramwell
5 (3)
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Hands-On Penetration Testing on Windows

Hands-On Penetration Testing on Windows

5 (3)
By: Phil Bramwell

Overview of this book

Windows has always been the go-to platform for users around the globe to perform administration and ad hoc tasks, in settings that range from small offices to global enterprises, and this massive footprint makes securing Windows a unique challenge. This book will enable you to distinguish yourself to your clients. In this book, you'll learn advanced techniques to attack Windows environments from the indispensable toolkit that is Kali Linux. We'll work through core network hacking concepts and advanced Windows exploitation techniques, such as stack and heap overflows, precision heap spraying, and kernel exploitation, using coding principles that allow you to leverage powerful Python scripts and shellcode. We'll wrap up with post-exploitation strategies that enable you to go deeper and keep your access. Finally, we'll introduce kernel hacking fundamentals and fuzzing testing, so you can discover vulnerabilities and write custom exploits. By the end of this book, you'll be well-versed in identifying vulnerabilities within the Windows OS and developing the desired solutions for them.
Table of Contents (19 chapters)
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Questions

  1. Fuzzing is one of the more popular attacks because it results in shellcode execution. (True | False)
  2. Identify the fuzzing points range 4 through 8 in this request: USER administrator.
  3. The Exception Offset in the Windows crash dump is the same value found in __________. 
  4. Name Metasploit's two tools used together to find the EIP offset in an overflow.
  1. An attacker has just discovered that if execution lands at 0x04a755b1, his NOP sled will be triggered and run down to his Windows shellcode. The vulnerable buffer is 2,056-bytes long and the shellcode is 546-bytes long. He uses the following line of code to prepare the shellcode: s = '\x90' * 1510 + buf + '\x04\xa7\x55\xb1'. Why is this attack bound to fail?

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