
Oracle Database 12c Security Cookbook
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This recipe explains a way to create a user with the same credentials on another database.
To complete this recipe, you'll need:
jessica
)create user
privilege, in the second database (for example, zoran
) $ sqlplus /
ddl
) that is used for user creation (for example, user jessica
): SQL> select dbms_metadata.get_ddl('USER', 'JESSICA') from
dual;
create user
privilege: $ sqlplus zoran@orcl2
SQL> create user "JESSICA" identified by values
'S:D82E6EF961F2EA7A878BCDDBC7E5C542BC148C4759D19A7
20A96BBF65658;H:F297A50FD538EF4AB119EB0278C9E72D;
C50B1E9C9AA52EC2';
In step 1, you used OS authentication to connect to the database.
In step 2, you found a DDL statement that has been used for user creation. This DDL statement may contain default
and temporary
tablespace assignments (note that even if you haven't explicitly assigned these tablespaces during user creation, the system will assign them implicitly using default values for the database). For instance, output in step 2 may look like this:
SQL> select dbms_metadata.get_ddl('USER', 'JESSICA') from dual;
DBMS_METADATA.GET_DDL('USER','JESSICA')
------------------------------------------------------------------
CREATE USER "JESSICA" IDENTIFIED BY VALUES 'S:D82E6EF961F2EA7A878BCDDBC7E5C542BC148C4759D19A720A96BBF65658;H:F297A50FD538EF4AB1 19EB0278C9E72D;C50B1E9C9AA52EC2'
DEFAULT TABLESPACE "USERS" TEMPORARY TABLESPACE "TEMP"
However, we used only the first part of this DDL in step 4 to create a user on the second database (and let the database decide about default tablespaces).
There is another way to accomplish the task.
You can only reveal the hash value of user's password (you cannot reveal the actual password).
This way requires select
on the sys.user$
table:
select
privilege on the sys.user$
table (for example, user who has the sysdba
privilege):$ sqlplus / as sysdba
jessica
):SQL> select spare4
from user$
where name='JESSICA';
create user
privilege:$ sqlplus zoran@orcl2
jessica
) using the hash value of the password that you have found in step 2:SQL> create user jessica identified by values
'S:2724193130FC67E7E23E3E44E33AF143F7A6C36489792B
5856133DCB331D;H:184895E50EA2FBCC2311ED76A3E5CF35;
T:BECCD5FC6F6E62BC34DF1C826AEE899EC6A6025FA0D5071659DA
7DD1ABB37763483B5C821E5A34C1184A56BE4B1C92CED79639D11101D
61B86ACBE60A30F19CC277D5753F7D3756DC1B7705C0ACE81F3';